| Name: | python34-pycurl |
|---|---|
| Version: | 7.43.0 |
| Release: | 7.el7 |
| Architecture: | x86_64 |
| Group: | Unspecified |
| Size: | 870730 |
| License: | LGPLv2+ or MIT |
| RPM: | python34-pycurl-7.43.0-7.el7.x86_64.rpm |
| Source RPM: | python3-pycurl-7.43.0-7.el7.src.rpm |
| Build Date: | Wed Dec 18 2019 |
| Build Host: | x86-ol7-builder-02.us.oracle.com |
| Vendor: | Oracle America |
| URL: | http://pycurl.io/ |
| Summary: | Python interface to libcurl for Python 3 |
| Description: | PycURL is a Python interface to libcurl. PycURL can be used to fetch objects identified by a URL from a Python program, similar to the urllib Python module. PycURL is mature, very fast, and supports a lot of features. Python 3.4 version. |
- Build for python3_other (bugz#1705680)
- Rebuilt to change main python from 3.4 to 3.6
- Fix build on EL6
- Add patch to build with python3 pyflakes
- EPEL7 version